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Kirchhoff's Law Example - Simple Method . Also Solution with Matrix Inversion Method - Hindi Urdu

Kirchhoff's Law Example - Simple Method . Also Solution with Matrix Inversion Method - Hindi Urdu Kirchhoff’s Laws Simple Example

In this example students learn how they can easily set the polarity of the elements of the circuit and how to define the loop direction . There is also solution with matrix inversion method. Which help the students to understand the implementation of matrix in real life.


From Loop ABCD
-20 + 4 I1 + 2 I2 = 0


4 I1 + 2 I2 = 20 ------- (i)


From Loop DCEF


-2 I2 + 3 I3 = 0 ------ (ii)


According to KCL


I1 = I2 + I3


I3 = 20/17


I3 = 1.176 A


Putting the value of I3 in Eq (ii)


-2 I2 + 3 (1.176) = 0


- 2 I2 = - 3.528


I2 = 1.764


We know that


I1 = I2 + I3


I1 = 1.764 + 1.176


I1 = 2.94 ≈ 3 A


For checking putting values of I2 and I3 in


Eq. (ii)


-2 (1.764)2 + 3(1.176) = 0


-3.528 + 3.528 = 0


-2 3 I2 = 0


3 4 I3 10


According to Matrix inversion Method


I2 = 1 Adj -2 3 0


I3 |A| 3 4 10


I2 = 1 4 -3 0


I3 (-2x4)-(3x3) -3 -2 10


I2 = 1 (4x0)+(-3x10)


I3 -17 (-3x0)+(-2x10)


I2 = 1 -30


I3 -17 -20





For I2 = -30/-17 = 1.76 A


For I3 = -20/-17 = 1.176 A


Same as our above solution.

Hindi

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